Question

a ball is thrown vertically upward. it has a sped of 10m/s when it has reached of its maximum heighr. how does the ball rise??

Answer 1

Answer on Question #53826, Physics / Mechanics | Kinematics | Dynamics

A ball is thrown vertically upward. It has a speed of $10\mathrm{m/s}$ when it has reached one half of its maximum height? How high does the ball rise?

Solution:

Using kinematics equation

$$v^{2} - v_{0}^{2} = 2aS$$

where $v$ is final velocity, $v_0$ is initial velocity, and $S$ is distance, we get

$$0^{2} - 10^{2} = -2 * 10 * \frac{h}{2}$$

where $a = -g = -10\ \mathrm{m/s^2}$

$$10h = 100$$

or the maximum height is

$$h = 10\ \mathrm{m}$$

Answer. The ball rise 5 m

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