Question #53484

w= theta/time
w/t = theta/time squared
dw/dt= dtheta/d time squared
a=dtheta/d time squared
where w is angular velocity and a is angular acceleration.
But this is wrong! a= d SQUARED theta/d time squared?
1

Expert's answer

2015-07-23T01:47:35-0400

Answer on Question #53484-Physics-Mechanics-Kinematics-Dynamics

w= theta/time

w/t = theta/time squared

dw/dt= dtheta/d time squared

a=dtheta/d time squared

where w is angular velocity and a is angular acceleration.

But this is wrong! a= d SQUARED theta/d time squared?

Solution

Angular velocity is


ω=dθdtθt.\omega = \frac {d \theta}{d t} \neq \frac {\theta}{t}.


Angular acceleration is


α=dωdt=ddt(dθdt)=d2θdt2.\alpha = \frac {d \omega}{d t} = \frac {d}{d t} \left(\frac {d \theta}{d t}\right) = \frac {d ^ {2} \theta}{d t ^ {2}}.


In addition we never use unpaired dd in the formulas for derivatives. We cannot use formulas such as


α=(dθdt2).\alpha = \left(\frac {d \theta}{d t ^ {2}}\right).


If t2t^2 is our variable we can write


α=(dθd(t2))\alpha = \left(\frac {d \theta}{d (t ^ {2})}\right)


when we use first derivative of θ\theta by t2t^2 .

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