Question #53337

A man walks 4 km towards north in one hour and 3 km towards east in the next hour.What is his average speed?
1

Expert's answer

2015-07-13T04:11:03-0400

Answer on Question 53337, Physics, Mechanics | Kinematics | Dynamics

Question:

A man walks 4 km towards north in one hour and 3 km towards east in the next hour. What is his average speed?

Solution:

By the definition, the formula for average speed looks like:


vavg=Total Distance CoveredTotal Time Taken=4km+3km1hour+1hour=7km2hour=3.5kmhour.v_{avg} = \frac{\text{Total Distance Covered}}{\text{Total Time Taken}} = \frac{4km + 3km}{1hour + 1hour} = \frac{7km}{2hour} = 3.5 \frac{km}{hour}.


Answer:


vavg=3.5kmhour.v_{avg} = 3.5 \frac{km}{hour}.


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