Question

An athlete on a trampoline leaps straight up into the air with an initial speed of 6.54 m/s. Find the maximum height reached by the athlete (in meters) relative to the trampoline. Use g=9.8 ms-2 and answer to 3 SF.

Answer 1

Question

An athlete on a trampoline leaps straight up into the air with an initial speed of $6.54\ \mathrm{m/s}$. Find the maximum height reached by the athlete (in meters) relative to the trampoline. Use $g = 9.8\ \mathrm{m/s}^2$ and answer to 3 SF.

Solution

The Law of conservation of energy:

$$\frac{m v_0^2}{2} = m g h;$$ $$h = \frac{v_0^2}{2g} = \frac{6.54^2}{2 * 9.8} \ m \approx 2.18\ \mathrm{m}$$

Answer: $h \approx 2.18\ \mathrm{m}$

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