Question #52134

A cricket ball of mass 150 gm is moving with velocity 12 m/s and is hit by a bat so that ball is turned back with 20 m/s. The force acts for 0.01s.The average force exerted by the bat on the ball is-
a)400 N b) 450 N c) 485 N d) 480 N
1

Expert's answer

2015-04-21T03:00:46-0400

Question

A cricket ball of mass 150g150\mathrm{g} is moving with velocity 12m/s12\mathrm{m/s} and is hit by a bat so that ball is turned back with 20m/s20\mathrm{m/s}. The force acts for 0.01 s. The average force exerted by the bat on the ball is

a) 400 N

b) 450 N

c) 485 N

d) 480 N

Solution

m=150g=0.15kg;vi=12m/s;vf=20m/s;Δt=0.01s.m = 150\mathrm{g} = 0.15\mathrm{kg}; \quad |v_i| = 12\mathrm{m/s}; \quad |v_f| = 20\mathrm{m/s}; \quad \Delta t = 0.01\mathrm{s}.


The second Newton's Law:


F=ma;\vec{F} = m \vec{a};F=mΔvΔt=mvfviΔt;F=mvf(vi)Δt=mvf+viΔt=480N\vec{F} = m \frac{\overrightarrow{\Delta v}}{\Delta t} = m \frac{\overrightarrow{v_f} - \overrightarrow{v_i}}{\Delta t}; \quad F = m \frac{|v_f| - (-|v_i|)}{\Delta t} = m \frac{|v_f| + |v_i|}{\Delta t} = 480\mathrm{N}


Answer: d) F=480NF = 480\mathrm{N}.

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