Question #52075

A particle moves according to the equation x=2t^2-5t+6.Find i) average velocity in the last 3 sec ii)Velocity at t=3s.
a) 1 m/s, 7 m/s b) 4 m/s,3 m/s c)2 m/s, 5 m/s d)3 m/s, 7 m/s
1

Expert's answer

2015-04-20T03:42:58-0400

Answer on Question #52075, Physics, Mechanics | Kinematics | Dynamics

A particle moves according to the equation x=2t25t+6x=2t^2-5t+6.

Find i) average velocity in the last 3 sec ii) Velocity at t=3s.

a) 1 m/s,7 m/s1 \mathrm{~m} / \mathrm{s}, 7 \mathrm{~m} / \mathrm{s} b) 4 m/s,3 m/s4 \mathrm{~m} / \mathrm{s}, 3 \mathrm{~m} / \mathrm{s} c) 2 m/s,5 m/s2 \mathrm{~m} / \mathrm{s}, 5 \mathrm{~m} / \mathrm{s} d) 3 m/s,7 m/s3 \mathrm{~m} / \mathrm{s}, 7 \mathrm{~m} / \mathrm{s}

Solution:

i) Average velocity


vav=ΔxΔt=x(3)x(0)30=963=1 m/sv_{av} = \frac{\Delta x}{\Delta t} = \frac{x(3) - x(0)}{3 - 0} = \frac{9 - 6}{3} = 1 \mathrm{~m/s}


ii) Velocity is


v=dxdt=4t5v = \frac{dx}{dt} = 4t - 5


Velocity at t=3st=3s

v(3)=435=7 m/sv(3) = 4 * 3 - 5 = 7 \mathrm{~m/s}


Answer: a) 1 m/s,7 m/s1 \mathrm{~m/s}, 7 \mathrm{~m/s}

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