Answer on Question #52075, Physics, Mechanics | Kinematics | Dynamics
A particle moves according to the equation x=2t2−5t+6.
Find i) average velocity in the last 3 sec ii) Velocity at t=3s.
a) 1 m/s,7 m/s b) 4 m/s,3 m/s c) 2 m/s,5 m/s d) 3 m/s,7 m/s
Solution:
i) Average velocity
vav=ΔtΔx=3−0x(3)−x(0)=39−6=1 m/s
ii) Velocity is
v=dtdx=4t−5
Velocity at t=3s
v(3)=4∗3−5=7 m/s
Answer: a) 1 m/s,7 m/s
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