Question #51862

The displacement of a particle along the X-axis is given as
x=5t2+1
, where x is in metres and t in seconds. Calculate its instantaneous velocity 2 s.
46 m/s
40 m/s
20 m/s
25 m/s
1

Expert's answer

2015-04-14T05:48:01-0400

Question

The displacement of a particle along the X-axis is given as x=5t2+1x = 5t^2 + 1, where xx is in metres and tt in seconds. Calculate its instantaneous velocity 2 s.

a) 46 m/s46\ \mathrm{m/s}

b) 40 m/s40\ \mathrm{m/s}

c) 20 m/s20\ \mathrm{m/s}

d) 25 m/s25\ \mathrm{m/s}

Solution

v(t)=dxdt=25t=10tv(t) = \frac{dx}{dt} = 2 * 5 * t = 10tv(2)=102=20 m/sv(2) = 10 * 2 = 20\ \mathrm{m/s}


Answer: c) v(2)=20 m/sv(2) = 20\ \mathrm{m/s}

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