Question #51853

Given three vectors
a⃗ =−i⃗ −4j⃗ +2k⃗
,
b⃗ =3i⃗ +2j⃗ −2k⃗
,
c⃗ =2i⃗ −3j⃗ +k⃗
, calculate
a⃗ ⋅(b⃗ ×c⃗ )

−6
6
9

−9
1

Expert's answer

2015-04-13T02:56:39-0400

Question

Given three vectors a=i4j+2ka = -i - 4j + 2k, b=3i+2j2kb = 3i + 2j - 2k, c=2i3j+kc = 2i - 3j + k, calculate a *(b×cb \times c)

a.-6

b.6

c.9

d.-9

Solution

a=(1;4;2);b=(3;2;2);c=(2;3;1);(a[b×c])?a = (-1; -4; 2); \quad b = (3; 2; -2); \quad c = (2; -3; 1); \quad (a^*[b \times c]) - ?


Firstly we find [b×c][b \times c]

[b×c]=(ijk322231)=i(21(3)(2))+j(2(2)31)+k(3(3)22)\begin{array}{l} [b \times c] = \left( \begin{array}{ccc} i & j & k \\ 3 & 2 & -2 \\ 2 & -3 & 1 \end{array} \right) \\ = i(2 * 1 - (-3) * (-2)) + j(2 * (-2) - 3 * 1) + k(3 * (-3) - 2 * 2) \end{array}[b×c]=4i5j5k;[b \times c] = -4i - 5j - 5k;(a[b×c])=1(4)+(4)(5)+2(5)=14(a^*[b \times c]) = -1 * (-4) + (-4) * (-5) + 2 * (-5) = 14


Answer: (a[b×c])=14(a^*[b \times c]) = 14. We don't have correct answer in given multiple choice answers.

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