a boy and his father run together.mass of the boy is half of his father ; kinetic energy of father is half of his son.if the father increases his velocity 1 m/s , then the kinetic energy becomes equal of each . what is their initial velocity?
if they run with their own kinetic energy on a road which is inclined and the road makes an angle of 30 degree with horizontal, how much distance will each of them complete ?
Yes, you are absolutely right. Find corrected answer in the
attachment.
tin
29.03.15, 11:56
we can do the last part like this for son , mgs sin (30)= K.E of
son=0.5m *(4.828)^2 , where s is the distance of son similarly for
father mgS sin (30)= K.E of father=0.5m *(2.4142)^2 , where S is the
distance of son is my process right??
tinn
29.03.15, 11:48
thanks for ur quick answer but why in the last part you use sin (2
alpha )? shouldn't it be sin (alpha)?
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Yes, you are absolutely right. Find corrected answer in the attachment.
we can do the last part like this for son , mgs sin (30)= K.E of son=0.5m *(4.828)^2 , where s is the distance of son similarly for father mgS sin (30)= K.E of father=0.5m *(2.4142)^2 , where S is the distance of son is my process right??
thanks for ur quick answer but why in the last part you use sin (2 alpha )? shouldn't it be sin (alpha)?
Leave a comment