a boy and his father run together.mass of the boy is half of his father ; kinetic energy of father is half of his son.if the father increases his velocity 1 m/s , then the kinetic energy becomes equal of each . what is their initial velocity?
if they run with their own kinetic energy on a road which is inclined and the road makes an angle of 30 degree with horizontal, how much distance will each of them complete ?
Yes, you are absolutely right. Find corrected answer in the
attachment.
tin
29.03.15, 11:56
we can do the last part like this for son , mgs sin (30)= K.E of
son=0.5m *(4.828)^2 , where s is the distance of son similarly for
father mgS sin (30)= K.E of father=0.5m *(2.4142)^2 , where S is the
distance of son is my process right??
tinn
29.03.15, 11:48
thanks for ur quick answer but why in the last part you use sin (2
alpha )? shouldn't it be sin (alpha)?
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Comments
Yes, you are absolutely right. Find corrected answer in the attachment.
we can do the last part like this for son , mgs sin (30)= K.E of son=0.5m *(4.828)^2 , where s is the distance of son similarly for father mgS sin (30)= K.E of father=0.5m *(2.4142)^2 , where S is the distance of son is my process right??
thanks for ur quick answer but why in the last part you use sin (2 alpha )? shouldn't it be sin (alpha)?