Question #51587

how many times more intense is 20 dB sound compared to 10dB sound.
1) 10time 2) 1/10 time. 3) 1/2 time. 4) 2 time.
1

Expert's answer

2015-03-26T11:16:24-0400

Answer on Question 51587, Physics, Mechanics | Kinematics | Dynamics

Question:

How many times more intense is 20dB sound compared to 10dB sound?

1) 10 times

2) 1/10 times

3) 1/2 times

4) 2 times

Solution:

In order to answer this question we use the decibel formula for comparison of sound power level:


IdB=10log10PP0I_{dB} = 10 \log_{10} \frac{P}{P_0}


where, IdBI_{dB} is the intensity in decibels, PP is the intensity of a sound source and P0P_0 is the measure of known intensity (the threshold of hearing for example).

Let us rearrange our formula:


IdB10=log10PP0\frac{I_{dB}}{10} = \log_{10} \frac{P}{P_0}10(IdB10)=PP010^{\left(\frac{I_{dB}}{10}\right)} = \frac{P}{P_0}


So, for the 20dB sound we have:


10(2010)=100=P20P010^{\left(\frac{20}{10}\right)} = 100 = \frac{P_{20}}{P_0}


And for the 10dB sound we have:


10(1010)=10=P10P010^{\left(\frac{10}{10}\right)} = 10 = \frac{P_{10}}{P_0}


Finally we obtain P20P10=10010=10\frac{P_{20}}{P_{10}} = \frac{100}{10} = 10 , therefore 20dB20dB sound is 10 times intense compared to 10dB10dB sound.

**Answer:**

1) 10 times

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