Question #51494

A bullet it shot vertically into the air with an initial velocity of 109.8 m/s. Calculate the time (in seconds) taken for the bullet to reach its maximum height.

Take gravitational acceleration to be 9.81 m/s2.
1

Expert's answer

2015-03-24T04:12:24-0400

Answer on Question #51494, Physics, Mechanics | Kinematics | Dynamics

Question:

A bullet it shot vertically into the air with an initial velocity of 109.8 m/s. Calculate the time (in seconds) taken for the bullet to reach its maximum height.

Take gravitational acceleration to be 9.81 m/s².

Answer:

A bullet will reach maximum height when v=0v = 0:


v=v0gt=0v = v_0 - g t = 0


where v0v_0 is initial velocity, gg is gravitational acceleration, tt is time.


t=v0g=109.8ms9.81ms2=11.19st = \frac{v_0}{g} = \frac{109.8 \frac{m}{s}}{9.81 \frac{m}{s^2}} = 11.19 \, s


Answer: 11.19 s

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