Question

a drop of some liquid of volume 0.04cm3 is placed on the surface of a glass slide.then another glass slide is placed on it such a way that the liquid forms a thin layer of area 20cm2 between the surface of the two slides.to separate the slids of force of 16*10^5dyne has to be applied normal to the surface.the surface tension of the liquid is in dyne/cm...

a) 60. b) 70. c) 80. d) 90

Answer 1

Answer to Question#51459 – Physics – Mechanics – Kinematics – Dynamics

Question

a drop of some liquid of volume $0.04\mathrm{cm}^3$ is placed on the surface of a glass slide. then another glass slide is placed on it such a way that the liquid forms a thin layer of area $20\mathrm{cm}^2$ between the surface of the two slides. to separate the slids of force of $16*10^5$ dyne has to be applied normal to the surface. the surface tension of the liquid is in dyne/cm...

a) 60. b) 70. c) 80. d) 90

Solution

$$16 * 10^5 \text{dyne} = 16N;$$ $$L = \frac{V}{S} = \frac{0.04}{20} = 0.002 \text{cm} = 0.2 \text{m};$$ $$\sigma = \frac{F}{L} = \frac{16}{0.2} = 80 \frac{H}{m} = 8 * 10^4 \frac{\text{dyne}}{\text{cm}};$$

Answer: c) $80 \frac{H}{m}$; $(8 \cdot 10^4 \frac{\text{dyne}}{\text{cm}})$;

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