Question #51383

A proton moves along the x axis according to the equation x = 62 t + 14 t^2, where x is in meters and t is in seconds. Calculate (a) the average velocity of the proton during the first 3.0 s of its motion, (b) the instantaneous velocity of the proton at t = 3.0 s, and (c) the instantaneous acceleration of the proton at t = 3.0 s.
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Expert's answer

2015-03-27T11:36:27-0400

Answer on Question #51383, Physics - Mechanics - Kinematics - Dynamics

Question A proton moves along the x axis according to the equation x=62t+14t2x=62t+14t^{2}, where x is in meters and t is in seconds. Calculate (a) the average velocity of the proton during the first 3.0 s of its motion, (b) the instantaneous velocity of the proton at t = 3.0 s, and (c) the instantaneous acceleration of the proton at t = 3.0 s.

Solution (a) Average velocity is total displacement divided by total time.

vˉ=st=x=623+14323=104m/s\bar{v}=\frac{s}{t}=\frac{x=62\cdot 3+14\cdot 3^{2}}{3}=104\,m/s

(b)instantaneous velocity is

v(t)=x(t)=62+28tv(t)=x^{\prime}(t)=62+28\cdot t

At t=3.0 :

v(3)=62+283=146m/sv(3)=62+28\cdot 3=146\,m/s

(c)instantaneous acceleration is

a(t)=v(t)=28a(t)=v^{\prime}(t)=28

At t=3.0 :

a(3)=28m/s2a(3)=28\,m/s^{2}

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