A basketball player grabbing a rebound jumps 76 cm vertically. How much total time (ascent and descent) does the player spend (a) in the top 13 cm of this jump and (b) in the bottom 13 cm? Do your results explain why such players seem to hang in the air at the top of a jump?
1
Expert's answer
2015-03-30T02:36:56-0400
a) we can answer the first part of this by recognizing the player rises 0.76m, reaches the apex of motion, and then falls back to the ground we can ask how long it takes to fall 0.13 m from rest: dist = 1/2 gt^2 or t=sqrt[2d/g] t=0.175 s this is the time to fall from the top; it would take the same time to travel upward the final 0.13 m, so the total time spent in the upper 0.15 m is 2x0.175 = 0.35s b) there are a couple of ways of finding thetime it takes to travel the bottom 0.13m first way: we can use d=1/2gt^2 twice to solve this problem the time it takes to fall the final 0.13 m is: time it takes to fall 0.76 m - time it takes to fall 0.63 m t = sqrt[2d/g] = 0.399 s to fall 0.76 m, and this equation yields it takes 0.359 s to fall 0.63 m, so it takes 0.04 s to fall the final 0.13 m. The total time spent in the lower 0.13 m is then twice this, or 0.08s
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment