Question

Given that the mass and radius of Jupiter are respectively 1:90 x 1027 kg and 7:15 x 104 km, calculate the escape
velocity from the surface of the planet

Answer 1

Answer on Question #51079 - Physics - Mechanics | Kinematics | Dynamics

1. Given that the mass and radius of Jupiter are respectively $1:90 \times 1027 \, \mathrm{kg}$ and $7:15 \times 104 \, \mathrm{km}$ , calculate the escape velocity from the surface of the planet

One can find the escape velocity: $\sqrt{v = \sqrt{\frac{2GM}{r}}}$ .

$$[ v ] = \sqrt {\frac {\frac {N \cdot m ^ {2}}{k g ^ {2}} \cdot k g}{m}} = \sqrt {\frac {N \cdot m}{k g}} = \sqrt {\frac {k g \cdot \frac {m}{s ^ {2}} \cdot m}{k g}} = \frac {m}{s}.$$ $$v = \sqrt {\frac {2 \cdot 6 . 6 7 \cdot 1 0 ^ {- 1 1} \cdot 1 . 9 \cdot 1 0 ^ {2 7}}{7 . 1 5 \cdot 1 0 ^ {7}}} = 5. 9 5 \cdot 1 0 ^ {4} \left(\frac {m}{s}\right).$$

Answer: $5.95 \cdot 10^{4} \frac{m}{s}$ .

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