Question

A monkey in a perch 20m high in a tree drops a coconut above the head of a zoo keeper as he runs with a speed 1.5m/s
beneath the tree. How far behind him in metres does the coconut hit the ground?

Answer 1

Answer to Question#51068 – Physics – Mechanics – Kinematics – Dynamics

To find time, we will use the falling of the coconut using the equation

$$\nabla S = \frac{1}{2} at^2 = -20m;$$

$a = \pm 10$ or $\pm 9.8$, depending on the acceleration of gravity. In this case, we will use -10 for simplicity. Now let's plug in.

$$\begin{array}{l} -20 = \frac{1}{2} (-10)t^2; \\ t = 2; \end{array}$$

Therefore, it takes two seconds for the coconut to hit the ground (and two seconds for the zookeeper to run, because these actions are happening simultaneously).

Now

$$\begin{array}{l} S = V \cdot t; \\ S = (1.5)2; \\ S = 3; \end{array}$$

Therefore, the zookeeper had run a total of $3\mathrm{m}$.

Answer is: $3\mathrm{m}$.

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