Question #50395

The sum of two forces, one having a magni- tude of 6 N acting due east and other having a magnitude of 7 N acting due north is
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Expert's answer

2015-01-13T11:23:41-0500

Answer on Question #50395 – Physics – Mechanics | Kinematics | Dynamics

The sum of two forces, one having a magnitude of 6 N acting due east and other having a magnitude of 7 N acting due north is

Solution:

We have two forces: F1=6NF_1 = 6N east, F2=7NF_2 = 7N north.

Using the Pythagorean Theorem:


F2=F12+F22F^2 = F_1^2 + F_2^2F=F12+F22=(6N)2+(7N)2=9.22NF = \sqrt{F_1^2 + F_2^2} = \sqrt{(6N)^2 + (7N)^2} = 9.22N


Answer: the sum of two forces is equal 9.22N9.22N

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