Question #50244

Water is pumped through a hose-pipe at a rate of 20 litres/mim and from the nozzle with the velocity 20 m/s. find the force of reaction on the nozzle in newton
and the usefull power of the pump in watt.
1

Expert's answer

2015-01-13T11:37:22-0500

Answer on the Question #50244, Physics, Mechanics | Kinematics | Dynamics

Given:


v=20msv = 20 \frac{m}{s}a=20litres/mina = 20 \text{litres/min}


Solution:


a=20litres/min=2060kgs=13kgsa = 20 \text{litres/min} = \frac{20}{60} \frac{\text{kg}}{\text{s}} = \frac{1}{3} \frac{\text{kg}}{\text{s}}


force:


F=va=203kgms2=203N6.67NF = v \cdot a = \frac{20}{3} \frac{\text{kg} \cdot \text{m}}{\text{s}^2} = \frac{20}{3} N \approx 6.67 N


usefull power:


P=Fst=Fv=203kgms220ms=4003kgm2s3=4003W133.3WP = \frac{F \cdot s}{t} = F \cdot v = \frac{20}{3} \frac{\text{kg} \cdot \text{m}}{\text{s}^2} \cdot 20 \frac{\text{m}}{\text{s}} = \frac{400}{3} \frac{\text{kg} \cdot \text{m}^2}{\text{s}^3} = \frac{400}{3} W \approx 133.3 W


Answer:


F=6.67NforceF = 6.67 N \quad \text{force}P=133.3Wusefull powerP = 133.3 W \quad \text{usefull power}


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