Question #50241

a train blowing its whistle moves with constant speed on a straight track towards observer and then crossed him.if the ratio of different between actua. and apparent frequency be 3:2 in two cases then the speed of train ...
1

Expert's answer

2015-01-06T12:39:09-0500

Answer on Question #50241, Physics, Mechanics | Kinematics | Dynamics

Question:

a train blowing its whistle moves with constant speed on a straight track towards observer and then crossed him. if the ratio of different between actual and apparent frequency be 3:2 in two cases then the speed of train ...

Answer:

The Doppler effect (or Doppler shift) is the change in frequency of a wave for an observer moving relative to its source. In classical physics the relationship between observed frequency ff and emitted frequency f0f_0 is given by:


f=c+vrc+vsf0f = \frac{c + v_r}{c + v_s} f_0


where cc is the velocity of waves in the medium;

vrv_r is the velocity of the receiver relative to the medium; positive if the receiver is moving towards the source (and negative in the other direction);

vsv_s is the velocity of the source relative to the medium; positive if the source is moving away from the receiver (and negative in the other direction).

In this case vr=0,vs=±vv_r = 0, v_s = \pm v.


f1=cc+vf0f_1 = \frac{c}{c + v} f_0f2=ccvf0f_2 = \frac{c}{c - v} f_0f0f1f2f0=23\frac{f_0 - f_1}{f_2 - f_0} = \frac{2}{3}cvc+v=23\frac{c - v}{c + v} = \frac{2}{3}v=c5=3405ms=68msv = \frac{c}{5} = \frac{340}{5} \frac{m}{s} = 68 \frac{m}{s}


Answer: 68ms68 \frac{m}{s}

http://www.AssignmentExpert.com/


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS