Question #50142

A car was moving with a velocity 24ms-1
. Suddenly the driver saw a child on his way, just 8m away from
the car. The driver immediately pressed the brakes. But it was too late; the car skidded to a halt at 12m.
What was the velocity of the car at the moment when it ran over the child?
1

Expert's answer

2014-12-28T06:22:08-0500

Answer on Question #50142, Physics, Mechanics | Kinematics | Dynamics

A car was moving with a velocity 24ms124\,\mathrm{ms}^{-1}. Suddenly the driver saw a child on his way, just 8m8\,\mathrm{m} away from the car. The driver immediately pressed the brakes. But it was too late; the car skidded to a halt at 12m12\,\mathrm{m}. What was the velocity of the car at the moment when it ran over the child?

Solution:

**Kinematics equation**


2ad=vi22ad = -v_i^2


where aa is acceleration, d=12md = 12\,\mathrm{m} is distance to stop, viv_i is initial velocity.

Thus,


a=vi22d=242212=24m/s2a = \frac{-v_i^2}{2d} = \frac{-24^2}{2 \cdot 12} = -24\,\mathrm{m/s^2}


**Again kinematics equation**


a=vf2vi22d2a = \frac{v_f^2 - v_i^2}{2d_2}vf=vi2+2ad2=2422248=83=13.86m/sv_f = \sqrt{v_i^2 + 2ad_2} = \sqrt{24^2 - 2 \cdot 24 \cdot 8} = 8\sqrt{3} = 13.86\,\mathrm{m/s}


**Answer:** vf=13.86m/sv_f = 13.86\,\mathrm{m/s}

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