Question #50141

It takes 3s for a sound wave to travel to a point 1km above the water surface from its source which is
kept under the water at a depth of hm. Determine the value of h, if it is given that velocity of sound in air
is 340ms-1
and in water is 1420ms-1
1

Expert's answer

2014-12-25T12:31:55-0500

Answer on Question #50141, Physics, Mechanics | Kinematics | Dynamics

It takes 3s for a sound wave to travel to a point 1km above the water surface from its source which is kept under the water at a depth of h m. Determine the value of h, if it is given that velocity of sound in air is 340 ms⁻¹ and in water is 1420 ms⁻¹.

Solution:

The time of travel is


t=t1+t2=3 st = t_1 + t_2 = 3 \text{ s}


where t1t_1 and t2t_2 are times of travel in water and air, respectively.


t1=h/vwatert_1 = h / v_{\text{water}}t2=dvair=1000 m340 m/st_2 = \frac{d}{v_{\text{air}}} = \frac{1000 \text{ m}}{340 \text{ m/s}}


Thus,


hvwater+dvair=t\frac{h}{v_{\text{water}}} + \frac{d}{v_{\text{air}}} = t


Hence,


h=vwater(tdvair)=1420(31000340)=142017=83.5 mh = v_{\text{water}} \left(t - \frac{d}{v_{\text{air}}}\right) = 1420 * \left(3 - \frac{1000}{340}\right) = \frac{1420}{17} = 83.5 \text{ m}


Answer: h=83.5 mh = 83.5 \text{ m}

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