Question #50133

You throw a ball vertically upward with a velocity 10 m/s. Find the maximum height it
will reach.
1

Expert's answer

2014-12-26T06:09:43-0500

Answer on Question 50133, Physics, Mechanics | Kinematics | Dynamics

Question:

You throw a ball vertically upward with a velocity 10 m/s10\ \mathrm{m/s}. Find the maximum height it will reach.

Solution:

In order to find the maximum height that ball will reach we can use the next equation:


vf2=vi2+2gh.v_f^2 = v_i^2 + 2gh.


Let's assume that axis yy is directed upward from the ground. We know that at the maximum height vf=0msv_f = 0\frac{m}{s}. So, we can solve this equation for hh:


0=(10ms)229.8ms2h,100m2s2=19.6ms2h,h=100m2s219.6ms2=5.102m.\begin{array}{l} 0 = \left(10\frac{m}{s}\right)^2 - 2 \cdot 9.8\frac{m}{s^2}h, \\ 100\frac{m^2}{s^2} = 19.6\frac{m}{s^2}h, \\ h = \frac{100\frac{m^2}{s^2}}{19.6\frac{m}{s^2}} = 5.102m. \end{array}


Answer:

The maximum height is h=5.102mh = 5.102m.

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