Answer on Question #50086 – Physics – Mechanics | Kinematics | Dynamics
Pressure and force
A pneumatic ram has a chamber piston diameter of 150 mm and is subjected to a variable source of pressure for actuation. What pressure will be required to produce an actuation force of 2 kN (consider the cylinder to be friction less)
Solution:
F=2kN=2000N−actuation force;d=150mm=0.15m−piston diameter;
Pressure is defined as force per unit area.
p=AreaForce=AF=10−4m25kg⋅9.8kgN=490kPaA=4πd2(2)in(1):p=4πd2F=πd24F=3.14⋅(0.15m)24⋅2000N=113.2kPa.
Answer: pressure is equal to p=113.2kPa.
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