Question

This question refers to: Laws of motion
A rubber ball of mass 0.12 kg moving at a speed of 25 m/s perpendicular to a smooth vertical wall, rebounds from the wall without loss of speed in an impact lasting 0.004 s
Calculate the impact force.
Give your answer in Newtons
Tip: consider the change of direction of the velocity before and after impact in your calculation. The answer could be a negative value.

Answer 1

Answer on Question 50082, Physics, Mechanics — Kinematics — Dynamics This question refers to: Laws of motion A rubber ball of mass 0.12 kg moving at a speed of 25 m/s perpendicular to a smooth vertical wall, rebounds from the wall without loss of speed in an impact lasting 0.004 s Calculate the impact force. Give your answer in Newtons Tip: consider the change of direction of the velocity before and after impact in your calculation. The answer could be a negative value.

Solution

Let us first find change of velocity of ball. It easy to understand that it will be

$\Delta v=25+25=50m/s$

Now we can use formula for change of impulse

$m\Delta v=F\Delta t$

Hence, impact force is

$F=\frac{m\Delta v}{\Delta t}=\frac{0.12\cdot 50}{0.004}=1.5\cdot 10^{3}\,N$

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