Question

Three blacks of masses 6kg, 4kg, 10kg are connected by mass less string on a frictionless table. They are pulled with a force T3 = 40N, Find T2.

Answer 1

Answer on Question # 50004 – Physics – Mechanics | Kinematics | Dynamics

**Given:**

$$\begin{array}{l} m_{1} = 6kg \quad m_{2} = 4kg \quad m_{3} = 10kg \\ T_{3} = 40\,N \\ \end{array}$$

**Find:** $T_{2}$

**Solution:**

We use the Newton's second law of motion

$$a = \frac{T_{3}}{m_{1} + m_{2} + m_{3}} = \frac{T_{2}}{m_{1} + m_{2}}$$

So

$$T_{2} = \frac{m_{1} + m_{2}}{m_{1} + m_{2} + m_{3}} T_{3} = \frac{10kg}{20kg} \cdot 40\,N = 20\,N$$

**Answer:** $T_{2} = 20\,N$

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