Question #49853

a toy car of mass 10kg is driving around a circle of radius 50cm with a centripetal acceleartion of 8 m/sec^2. What is the speed of the car?
1

Expert's answer

2014-12-08T12:45:28-0500

Answer on Question 49853, Physics, Mechanics | Kinematics | Dynamics

Question:

A toy car of mass 10kg10kg is driving around a circle of radius 50cm50cm with a centripetal acceleration of 8ms28\frac{m}{s^2}. What is the speed of the car?

Solution:

By the definition of the centripetal acceleration we have:


ac=v2R,a_c = \frac{v^2}{R},


where aca_c is the centripetal acceleration of the car, vv is the speed of the car, RR is the radius of the circle.

From this formula we can obtain the speed of the car:


v=acR=8ms20.5m=2ms.v = \sqrt{a_c R} = \sqrt{8 \frac{m}{s^2} \cdot 0.5m} = 2 \frac{m}{s}.


Answer:

The speed of the car is v=2msv = 2\frac{m}{s}.

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