Question

a projectile is launched horizontally with a speed of 86.7 m/s. if the projectile is launched 1.6 m above the floor, how long will it take the projectile to hit the floor

Answer 1

Answer on Question 49839, Physics, Mechanics

Question:

A projectile is launched horizontally with a speed of 86.7 m/s. If the projectile is launched 1.6 m above the floor, how long will it take the projectile to hit the floor?

Solution:

Let's find how long will it take the projectile to hit the floor:

$$y = v _ {i y} t + \frac {1}{2} g t ^ {2}.$$

Because the y-component of initial velocity $v_{iy} = 86.7\frac{m}{s}\cdot \sin 0{}^{\circ} = 0$ we obtain:

$$y = h = \frac {1}{2} g t ^ {2},$$ $$t = \sqrt {\frac {2 h}{g}} = \sqrt {\frac {2 \cdot 1 . 6 m}{9 . 8 \frac {m}{s ^ {2}}}} = 0. 5 7 s.$$

Answer:

$$t = 0. 5 7 s.$$

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