Question #49632

a connon ball has a range R on a horizontal plane.If h and h' are the greatest heights in the two paths for which this is possible ,then
1

Expert's answer

2014-12-01T12:58:28-0500

Answer on Question #49632-Physics-Mechanics-Kinematics-Dynamics

A cannon ball has a range R on a horizontal plane. If h and h' are the greatest heights in the two paths for which this is possible, then


R=4hh.R = 4 \sqrt {h h ^ {\prime}}.

Solution

The two angles are complimentary.


h=u2sin2θ2g;h=u2sin2(90θ)2g=u2cos2θ2g.h = \frac {u ^ {2} \sin^ {2} \theta}{2 g}; h ^ {\prime} = \frac {u ^ {2} \sin^ {2} (9 0 - \theta)}{2 g} = \frac {u ^ {2} \cos^ {2} \theta}{2 g}.


And


R=u2sin2θg=2u2sinθcosθg.R = \frac {u ^ {2} \sin 2 \theta}{g} = \frac {2 u ^ {2} \sin \theta \cos \theta}{g}.


But


sinθ=2ghu2,cosθ=2ghu2.\sin \theta = \sqrt {\frac {2 g h}{u ^ {2}}}, \cos \theta = \sqrt {\frac {2 g h ^ {\prime}}{u ^ {2}}}.


Therefore


R=2u2g2ghu22ghu2=4hh.R = \frac {2 u ^ {2}}{g} \sqrt {\frac {2 g h}{u ^ {2}}} \sqrt {\frac {2 g h ^ {\prime}}{u ^ {2}}} = 4 \sqrt {h h ^ {\prime}}.


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