Question #49631

The lap joint is fastened togetherusing two bolts. determine the required diameter of the bolts if the allowable shear stress for the bolts is 60MPa and the allowable bearing stress in the plates is 110MPa. Assume each bolt supports an equal portion of the load and the thickness of each plate is 20 mm. Express the answer in millimeters.
1

Expert's answer

2015-01-21T11:08:25-0500

Answer on Question#49631 - Physics - Mechanics - Kinematics - Dynamics

The lap joint is fastened together using two bolts. Determine the required diameter of the bolts if the allowable shear stress for the bolts is τ=60MPa\tau = 60\mathrm{MPa} and the allowable bearing stress in the plates is σ=110MPa\sigma = 110\mathrm{MPa} . Assume each bolt supports an equal portion of the load and the thickness of each plate is t=20mmt = 20\mathrm{mm} . Express the answer in millimeters.

Solution:



From the shearing of two bolts


F=2τAboltF = 2 \cdot \tau \cdot A _ {b o l t}


where Abolt=πd24A_{bolt} = \frac{\pi d^2}{4} is a cross-section of the bolt.

Therefore


F=τπd22F = \tau \cdot \frac {\pi d ^ {2}}{2}


From bearing of plate material


F=2σAF = 2 \cdot \sigma \cdot A


where A=dtA = d \cdot t is a cross-section of the plate, which is born.

Therefore


F=2σdtF = 2 \cdot \sigma \cdot d \cdot t


Using equations (1) and (2) we obtain


τπd22=2σdt\tau \cdot \frac {\pi d ^ {2}}{2} = 2 \cdot \sigma \cdot d \cdot t


or, equivalently


d=4σπτt=4π110MPa60MPa20mm=47mmd = \frac {4 \sigma}{\pi \tau} t = \frac {4}{\pi} \frac {110 \mathrm{MPa}}{60 \mathrm{MPa}} 20 \mathrm{mm} = 47 \mathrm{mm}


Answer: d=4σπτt=47mm.d = \frac{4\sigma}{\pi\tau} t = 47 \mathrm{mm}.

https://www.AssignmentExpert.com

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS