Question

A wagon is pulled by a handle making an upward angle of 25 degrees from the horizontal with a force of 25 N. What is the horizontal force pulling the wagon forward? What is the upward force lifting the wagon off the road?

Show work please, so I can know how to do it.

Answer 1

Let's make projection on the coordinate axes:
Fh = F*cosα = 25*cos(25°) = 22,66 N - horizontal force component;
Fv = F*sinα = 25*sin(25°) = 10,57 N - vertical force component.