A wagon is pulled by a handle making an upward angle of 25 degrees from the horizontal with a force of 25 N. What is the horizontal force pulling the wagon forward? What is the upward force lifting the wagon off the road?
Show work please, so I can know how to do it.
1
Expert's answer
2011-11-03T12:13:01-0400
Let's make projection on the coordinate axes: Fh = F*cosα = 25*cos(25°) = 22,66 N - horizontal force component; Fv = F*sinα = 25*sin(25°) = 10,57 N - vertical force component.
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