Question #49252

a stationary object is released from a point P at a distance 3R from the centre of the moon which has radius R and mass M. Whiich of the following gives the speed of the object on hitting the moon?
1. (2GM/3R)^1/2
2. (4GM/3R)^1/2
3. (GM/3R)^1/2
4. (GM/R)^1/2
1

Expert's answer

2015-06-01T01:36:08-0400

Answer on Question #49237 – Physics – Mechanics | Kinematics | Dynamics

1. A stationary object is released from a point P at a distance 3R from the centre of the moon which has radius R and mass M. Which of the following gives the speed of the object on hitting the moon?

1. (2GM/3R)^1/2;

2. (4GM/3R)^1/2;

3. (GM/3R)^1/2;

4. (GM/R)^1/2.

Solution.

We must use the law of conservation and transformation of energy. The sum of the potential energy of an object and its kinetic energy remain constant:


GmM3R+mv022=GmMR+mv122,- G \frac {m M}{3 R} + \frac {m \cdot v _ {0} ^ {2}}{2} = - G \frac {m M}{R} + \frac {m \cdot v _ {1} ^ {2}}{2},


where mm is the object mass, v0(v1)v_{0}(v_{1}) is its initial (final) speed.

The object was stationary, so v0=0v_{0} = 0.

Thus, we can find the speed of the object on hitting the moon.


GM3R=GMR+v122,v122=2GM3R,v1=2GM3R.- G \frac {M}{3 R} = - G \frac {M}{R} + \frac {v _ {1} ^ {2}}{2}, \quad \frac {v _ {1} ^ {2}}{2} = \frac {2 G M}{3 R}, \quad v _ {1} = 2 \sqrt {\frac {G M}{3 R}}.


Answer: 2)

http://www.AssignmentExpert.com/


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
15.12.16, 19:41

Dear Ashish, this is wrong way since the acceleration of the object is not uniform for such large distances.

Ashish
09.12.16, 01:31

Why cannot we use Acceleration = GM/9R^2 And use third equation of motion V^2 -u^2 = 2 a s Where s= 2R U=0 Answer do not match then

LATEST TUTORIALS
APPROVED BY CLIENTS