Question #49189

The temperature of a 1 m long aluminum rod is 20° C. If the temperature is increased to 70° C, what is the
length of the rod?
1

Expert's answer

2014-12-15T12:15:01-0500

Answer on Question 49189, Physics, Mechanics | Kinematics | Dynamics

Question:

The temperature of a 1 m long aluminum rod is 20°C. If the temperature is increased to 70°C, what is the length of the rod?

Solution:

By the definition of the linear thermal expansion we have:


ΔLa=αaL0aΔT,\Delta L _ {a} = \alpha_ {a} L _ {0 a} \Delta T,


where ΔLa\Delta L_{a} is the change in the length of the aluminum rod after the change of temperature, αa=23106C1\alpha_{a} = 23\cdot 10^{-6}\mathrm{{}^\circ C^{-1}} is the coefficient of linear expansion for aluminum, L0aL_{0a} is the length of the aluminum rod before the change of temperature, ΔT\Delta T is the change of temperature.

Therefore, substituting all data from condition of the problem to the formula for linear thermal expansion we obtain:


ΔLa=23106C11m(70C20C)=0.00115m.\Delta L _ {a} = 23 \cdot 10^{-6} \mathrm{{}^\circ C^{-1}} \cdot 1 \mathrm{m} \cdot (70{}^{\circ} \mathrm{C} - 20{}^{\circ} \mathrm{C}) = 0.00115 \mathrm{m}.


Then the length of the aluminum rod would be:


L=L0a+ΔLa=1m+0.00115m=1.00115m.L = L _ {0 a} + \Delta L _ {a} = 1 \mathrm{m} + 0.00115 \mathrm{m} = 1.00115 \mathrm{m}.


Answer:

The length of the aluminum rod is 1.00115 meters.

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