Question #49183

Suppose that you balance a 5 kg ball on the tip of your finger that has an area of 1 cm2. What is the pressure
on your finger?
1

Expert's answer

2014-12-16T13:10:30-0500

Answer on Question #49183 – Physics - Mechanics | Kinematics | Dynamics

Suppose that you balance a 5 kg ball on the tip of your finger that has an area of 1 cm². What is the pressure on your finger?

Solution:

m = 5kg – mass of the ball;

A = 1 cm² = 10⁻⁴ m² – area of the tip of the finger;

p – pressure on the finger;

Pressure is defined as force per unit area.


p=ForceArea=FA=mgA=5kg9.8Nkg104m2=490 kPap = \frac{\text{Force}}{\text{Area}} = \frac{F}{A} = \frac{mg}{A} = \frac{5kg \cdot 9.8 \frac{N}{kg}}{10^{-4}m^2} = 490 \text{ kPa}


Answer: pressure is equal to 490 kPa.

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