Question #49182

A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does
the ball make it over the fence?
1

Expert's answer

2014-11-21T00:59:09-0500

Answer on Question #49182 – Physics – Mechanics | Kinematics | Dynamics

1. A ball is thrown at 22m/s22 \, \text{m/s} at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does the ball make it over the fence?


{x=v0cosφty=v0sinφtgt22\left\{ \begin{array}{l} x = v_0 \cos \varphi \cdot t \\ y = v_0 \sin \varphi \cdot t - \frac{g t^2}{2} \end{array} \right.


The total time of a fly (without any obstacles) can be found from the equation y=0y = 0:


v0sinφtgt22=0,t1=2v0sinφg=222sin459.83.17(s).v_0 \sin \varphi \cdot t - \frac{g t^2}{2} = 0, \quad t_1 = \frac{2 v_0 \sin \varphi}{g} = \frac{2 \cdot 22 \cdot \sin 45{}^\circ}{9.8} \approx 3.17 \, (\text{s}).


The total distance in XX-direction will be x(t1)=v0cosφt1=22cos453.17=49.3(m)x(t_1) = v_0 \cos \varphi \cdot t_1 = 22 \cdot \cos 45{}^\circ \cdot 3.17 = 49.3 \, (\text{m}).

x(t1)<l=100mx(t_1) < l = 100 \, \text{m}, so, the ball will drop before the fence.

Answer: the ball will not make the fence over.

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