Question #49062

A car of mass 1000 kg is cruising at 120 km/hr. At this velocity the drag and friction forces that the engine needs to work against is equivalent to 450 N.


Q: Calculate the kinetic energy of the car when cruising at 120 km/hr.
Give your answer in Joules
1

Expert's answer

2014-11-18T12:53:45-0500

Answer on Question #49062 – Engineering – Other

1. A car of mass 1000kg1000\,\mathrm{kg} is cruising at 120kmhr120\,\mathrm{kmhr}. At this velocity the drag and friction forces that the engine needs to work against is equivalent to 450N450\,\mathrm{N}.

Q Calculate the kinetic energy of the car when cruising at 120kmhr120\,\mathrm{kmhr}.

Give your answer in Joules.


m=103kgv=120kmhr=33.3msF=450NE?\begin{array}{l} m = 10^{3}\,\mathrm{kg} \\ v = 120\,\frac{\mathrm{km}}{\mathrm{hr}} = 33.3\,\frac{\mathrm{m}}{\mathrm{s}} \\ F = 450\,\mathrm{N} \\ \hline E - ? \end{array}


Solution.

The kinetic energy of an object, which has a mass mm and moves with the speed vv is


E=mv22.E = \frac{mv^2}{2}.


Let check the dimension: [E]=kg(ms)2=Nm=J[E] = kg \cdot \left(\frac{m}{s}\right)^2 = N \cdot m = J.

Let evaluate the quantity: E=10333.322=5.54105(J)E = \frac{10^{3} \cdot 33.3^{2}}{2} = 5.54 \cdot 10^{5}(J).

Answer: 5.541055.54 \cdot 10^{5} Joules.

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