Question #48838

On Jupiter a day lasts for 9.9 earth hours and the circumference at the equator is
448600 km. If the measured value of gravitational acceleration at the equator is 24 6. ms ,−2
what is the true gravitational acceleration and the centrifugal acceleration.
1

Expert's answer

2014-11-13T03:10:28-0500

Answer on Question 48838, Physics, Mechanics — Kinematics — Dynamics On Jupiter a day lasts for 9.9 earth hours and the circumference at the equator is 448600 km. If the measured value of gravitational acceleration at the equator is 24.6 ms ,-2 what is the true gravitational acceleration and the centrifugal acceleration.

Solution

Angular velocity is

ν=2π9.936000.0000282πs1\nu=\frac{2\pi}{9.9\cdot 3600}\approx 0.000028\cdot 2\pi\,s^{-1}

Hence, centrifugal acceleration is

a=ν2r=0.0001764486001032π0.353m/s2a=\nu^{2}r=0.000176\cdot\frac{448600\cdot 10^{3}}{2\pi}\approx 0.353m/s^{2}

True gravitational acceleration then is

g=24.60.35324.2m/s2g=24.6-0.353\approx 24.2m/s^{2}

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