Question #48704

which requires more force to stop if they have the same acceleration : sumo wrestler or fairy? Explain why?
1

Expert's answer

2014-11-10T03:49:19-0500

Answer on Question #48704 – Physics - Mechanics | Kinematics | Dynamics

which requires more force to stop if they have the same acceleration : sumo wrestler or fairy? Explain why?

Solution:

MM – The mass of the sumo wrestler;

mm – The mass of the fairy;

as=af=aa_{s} = a_{f} = a – acceleration of the wrestler and fairy;

FsF_{s} – force we must apply to stop sumo wrestler;

FfF_{f} – force we must apply to stop fairy;

According to the Newton's Second law:


F=massaccelerationF = \text{mass} \cdot \text{acceleration}


Hence, we must apply some forces FsF_{s} and FfF_{f} of our bodies to stop their motion:

Force to stop sumo wrestler:


Fs=Mas=MaF_{s} = M \cdot a_{s} = M \cdot a


Force to stop fairy:


Ff=maf=maF_{f} = m \cdot a_{f} = m \cdot a


If the M>mM > m (mass of the wrestler is bigger then mass of the fairy)


Fs>FfF_{s} > F_{f}


Thus, more force requires to stop sumo wrestler.

Answer: more force requires to stop sumo wrestler.

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