Question

The accelaration of a particle travelling at a speed of 40m/s going ground a curve of radious 16m is

Answer 1

Answer on Question 48683, Physics, Mechanics | Kinematics | Dynamics |

Question:

The acceleration of a particle travelling at a speed of $40\,\mathrm{m/s}$ going around a curve of radius $16\,\mathrm{m}$ is?

Solution:

When particle going around a curve, the acceleration will be directed toward the center of a curve. The acceleration in this case would be:

$$a = \frac{v^2}{r} = \frac{\left(40 \frac{m}{s}\right)^2}{16\,m} = 100 \frac{m}{s^2}.$$

Answer:

The acceleration of a particle is $100 \frac{m}{s^2}$.

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