Question

coefficient of static friction is .36
coefficient of kinetic friction is .30
weight of box 400N

how much force is needed to keep the box moving

Answer 1

Answer on Question 48638, Physics, Mechanics | Kinematics | Dynamics

Question:

Coefficient of static friction is 0.36, coefficient of kinetic friction is 0.30, weight of box 400N. How much force is needed to keep the box moving?

Solution:

From conditions of the problem we have: $\mu_s = 0.36$ is the coefficient of static friction, $\mu_k = 0.30$ is the coefficient of kinetic friction and weight of box is $w = 400N$ . Because we are asking about how much force is needed to keep the box moving, we need to find the force of kinetic friction:

$$F = F _ {k},$$ $$F _ {k} = \mu_ {k} w.$$

So, we obtain: $F = 0.30 \cdot 400N = 120N$ .

Answer:

The force is needed to keep the box moving would be 120N.

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