Question

Two cars X and Y are travelled in the same direction with velocity V1 and V2 (V1> V2).when the car X is at a distdistance S behind the car Y,the car X starts deaccelaration with A.to avoid the collision......

Answer 1

Answer on Question #48632, Physics, Mechanics | Kinematics | Dynamics

Two cars X and Y are travelled in the same direction with velocity V1 and V2 (V1> V2). When the car X is at a distance S behind the car Y, the car X starts deacceleration with a. To avoid the collision...

Solution:

The relative velocity of car X is $v_{1} - v_{2}$.

The kinematic equation that describes an object's motion is:

$$d = \frac{(v_{1} - v_{2})^{2}}{2a}$$

The symbol $d$ stands for the distance that will cover car X to reach car Y.

To avoid the collision

$$S \geq d$$

Answer: $S \geq \frac{(v_{1} - v_{2})^{2}}{2a}$

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