Question

A mass tied to a string moves in a verticle circle with a uniform speed of 5 m/s at the point where the string is horizontal breaks. the mass will reach a height above that point will be nearly (radius =1m)

Answer 1

Answer on Question #48600, Physics, Mechanics | Kinematics | Dynamics

A mass tied to a string moves in a vertical circle with a uniform speed of $5\,\mathrm{m/s}$ at the point where the string is horizontal breaks. The mass will reach a height above that point will be nearly (radius = 1 m)

Solution:

The kinematic equation that describes an object's motion is:

$$2ah = v_f^2 - v_0^2$$

where $a$ is acceleration, $h$ is coordinate, $v_0$ is initial velocity and $v$ is final velocity.

$v_0 = v$ and $v_f = 0$.

$a = g = -9.81\,\mathrm{m/s^2}$ is acceleration.

Thus,

$$h = \frac{-v_0^2}{2g} = \frac{-5^2}{-2 \cdot 9.81} = 1.27\,\mathrm{m}$$

Answer: $h = 1.27\,\mathrm{m}$

http://www.AssignmentExpert.com/