Question #48439

"Ken Ranfast is the star of the cross-country team. During the recent morning run, Ken averaged a speed of 5.8m/s for 12.9 minutes. Ken then averaged a speed of 6.10 m/s for 7.1 minutes. Determine the total distance which ken ran during his 20 minute jog."
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Expert's answer

2014-11-03T00:50:46-0500

Answer on Question 48439, Physics, Mechanics | Kinematics | Dynamics

Question:

Ken Ranfast is the star of the cross-country team. During the recent morning run, Ken averaged a speed of 5.8m/s for 12.9 minutes. Ken then averaged a speed of 6.10 m/s for 7.1 minutes. Determine the total distance which Ken run during his 20 minute jog.

Solutions:

The total distance is the sum of distances which Ken run with a speed of 5.8m/s for 12.9 minutes and a speed of 6.10m/s for 7.1 minutes respectively. Therefore we obtain:


d=S1t1+S2t2=5.8ms12.960s+6.1ms7.160s=7088md = S _ {1} \cdot t _ {1} + S _ {2} \cdot t _ {2} = 5.8 \frac {m}{s} \cdot 12.9 \cdot 60 s + 6.1 \frac {m}{s} \cdot 7.1 \cdot 60 s = 7088 m


Answer:

Total distance is 7088 meters.

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