Question #48382

A bird generates a lift of 3 x 10^1 N at its maximum velocity of 14m/s, the bird has a mass of .020kg what is the tightest radius that it can turn and maintain its altitude?
1

Expert's answer

2014-10-31T01:40:04-0400

Answer on Question #48382, Physics, Mechanics | Kinematics | Dynamics

A bird generates a lift of 3×101N3 \times 10^1 \, \text{N} at its maximum velocity of 14m/s14 \, \text{m/s}, the bird has a mass of 0.020kg0.020 \, \text{kg} what is the tightest radius that it can turn and maintain its altitude?

Solution:

The force equation


ma=Fmgma = F - mg


where aa is the centripetal acceleration, a=V2Ra = \frac{V^2}{R}.


m(a+g)=m(v2R+g)=Tm(a + g) = m\left(\frac{v^2}{R} + g\right) = T


Thus,


a=Fmgm=Fmg=30N0.020kg10ms2=1490m/s2a = \frac{F - mg}{m} = \frac{F}{m} - g = \frac{30 \, \text{N}}{0.020 \, \text{kg}} - 10 \, \frac{\text{m}}{\text{s}^2} = 1490 \, \text{m/s}^2v2R=a\frac{v^2}{R} = a


Thus,


R=av2=1490142=7.6mR = \frac{a}{v^2} = \frac{1490}{14^2} = 7.6 \, \text{m}


Answer: R=7.6mR = 7.6 \, \text{m}

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