Question

A centrifuge is used and runs at 3600 rpm. When it is shut off it comes to a stop. If it completed 30 revolutions in the time from the maximum speed to when it stopped, what was the angular accelerations assuming it was constant?

Answer 1

Answer on Question #48379, Physics, Mechanics | Kinematics | Dynamics

Question:

A centrifuge is used and runs at 3600 rpm. When it is shut off it comes to a stop. If it completed 30 revolutions in the time from the maximum speed to when it stopped, what was the angular accelerations assuming it was constant?

Answer:

Angle equals:

$$\phi = \frac {\omega^ {2}}{2 \beta}$$

where $\beta$ is angular acceleration, $\omega = 2\pi \frac{3600}{60} \frac{rad}{s}$ is angular speed

$$\phi = 2 \pi 30 rad$$

Therefore:

$$\beta = \frac {\omega^ {2}}{2 \beta} = 377 \frac{rad}{s^2}$$

Answer: $377\frac{rad}{s^2}$

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