Question #48290

if a lift goes up and down with constant velocity then how the time period change? when it will decrease or increase?

if the lift moves with constant acceleration then how the time period will change?please explain in both questions
1

Expert's answer

2014-11-03T10:08:28-0500

Answer on Question #48290, Physics, Mechanics | Kinematics | Dynamics

If a lift goes up and down with constant velocity then how the time period change? When it will decrease or increase?

If the lift moves with constant acceleration then how the time period will change? Please explain in both questions.

Solution:

In first case, when a lift goes with constant velocity the period of pendulum will be


T=2πLg,T = 2 \pi \sqrt {\frac {L}{g}},


where gg is the acceleration due to gravity.

Period of pendulum in second case depends from circumstances when the lift acceleration coincides with the gravitational acceleration or not. When the acceleration is coincide with free fall acceleration the period is going to be larger:


T=2πLga,T = 2 \pi \sqrt {\frac {L}{g - a}},


otherwise it will decrease


T=2πLg+a.T = 2 \pi \sqrt {\frac {L}{g + a}}.


https://www.AssignmentExpert.com

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
03.11.14, 17:07

We're sorry for the misunderstanding. Check updated answer.

tinu
01.11.14, 20:20

i have asked time period of a simple pendulum in lift . it the lift moves up with 2 m/s^2 acceleration, the neat acceleration will be =g+2 so now the time period will change . but you say time period will not change when acceleration is constant.why?? and for constant velocity, will the time period change??

LATEST TUTORIALS
APPROVED BY CLIENTS