Question #48098

What is the μ of between a 520 kg wooden crate and the concrete ramp (15º) that it is sitting on?
1

Expert's answer

2014-10-22T01:21:30-0400

Answer on Question #48098, Physics, Mechanics | Kinematics | Dynamics

What is the μ\mu of between a 520kg520\mathrm{kg} wooden crate and the concrete ramp (15°) that it is sitting on?

Solution.

1st1^{\mathrm{st}} Newton's law:


F=0\sum \vec {F} = 0mgcosα=Nm g \cdot \cos \alpha = Nmgsinα=Ffm g \cdot \sin \alpha = F _ {f}Ff=μNF _ {f} = \mu N


So:


mgsinα=μmgcosαm g \cdot \sin \alpha = \mu m g \cdot \cos \alphaμ=tanα=tan150.27\mu = \tan \alpha = \tan 1 5 {}^ {\circ} \approx 0. 2 7


Answer: μ0.27\mu \approx 0.27

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