Question

A skydiver jumps from a helicopter hovering at high altitude.
Neglecting air resistance, how fast will she be falling 12 after jumping?
How far will she have fallen?
What us her average velocity

Answer 1

Answer on Question 48073, Physics, Mechanics | Kinematics | Dynamics

Question:

A skydiver jumps from a helicopter hovering at high altitude. Neglecting air resistance, how fast will she be falling 12s. after jumping? How far will she have fallen? What is her average velocity?

Solution:

For the case of object falling without air resistance we have:

$$V_{fall} = g \cdot t + V_0, \quad V_0 = 0$$

So, $V_{fall} = g \cdot t = \left(9.8 \frac{m}{s^2}\right) \cdot 12s = 117.6 \frac{m}{s}$

To find how far will she fallen we use another formula:

$$y = \frac{1}{2} \cdot g \cdot t^2 + V_0 \cdot t + y_0, \quad V_0 = 0, \quad y_0 = 0$$

So, $y = \frac{1}{2} \cdot 9.8 \frac{m}{s^2} \cdot (12s)^2 = 705.6m$

And finally we obtain average velocity:

$$V_{avr} = \frac{y}{t} = \frac{705.6}{12} = 58.8 \frac{m}{s}$$

Answer:

$$V_{fall} = 117.6 \frac{m}{s}$$ $$y = 705.6m$$ $$V_{avr} = 58.8 \frac{m}{s}$$

https://www.AssignmentExpert.com