Question #48058

A beam 5m long is supported at it's ends A and B point load W1&W2 were placed at C and D, 1m and 3m respectively from A. If the reaction at A is twice the reaction at B, find the ration of the loadss W1&W2...
1

Expert's answer

2014-10-23T01:32:26-0400

Answer on Question #48058, Physics, Mechanics | Kinematics | Dynamics

A beam 5m long is supported at it's ends A and B point load W1&W2 were placed at C and D, 1m and 3m respectively from A. If the reaction at A is twice the reaction at B, find the ration of the loadss W1&W2...



Let NAN_A and NBN_B be the reaction forces at the left and right supports.

Taking moments of all forces about the point of contact of the left support,


W1AC+W2ADNBAB=0W _ {1} * A C + W _ {2} * A D - N _ {B} * A B = 0W1+3W25NB=0W _ {1} + 3 W _ {2} - 5 N _ {B} = 0


Thus,


NB=W1+3W25N _ {B} = \frac {W _ {1} + 3 W _ {2}}{5}


Taking moments of forces about the point of contact of the right support,


NAABW1CBW2DB=0N _ {A} * A B - W _ {1} * C B - W _ {2} * D B = 05NA4W12W2=05 N _ {A} - 4 W _ {1} - 2 W _ {2} = 0


Thus,


NA=4W1+2W25N _ {A} = \frac {4 W _ {1} + 2 W _ {2}}{5}


From given


NANB=2\frac {N _ {A}}{N _ {B}} = 2NANB=4W1+2W2W1+3W2=2\frac {N _ {A}}{N _ {B}} = \frac {4 W _ {1} + 2 W _ {2}}{W _ {1} + 3 W _ {2}} = 24W1+2W2=2(W1+3W2)4 W _ {1} + 2 W _ {2} = 2 \left(W _ {1} + 3 W _ {2}\right)4W1+2W2=2W1+6W24 W _ {1} + 2 W _ {2} = 2 W _ {1} + 6 W _ {2}2W1=4W22 W _ {1} = 4 W _ {2}


Thus,


W1W2=2\frac {W _ {1}}{W _ {2}} = 2


Answer: W1W2=2\frac{W_1}{W_2} = 2

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