Question #47985

A stone is dropped at rest from the top of a cliff. it is observed to hit the ground 5.78s later it falls an acceleration of -10m/s2. How high is the cliff?
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Expert's answer

2014-10-20T09:50:00-0400

Answer on Question #47985, Physics, Mechanics | Kinematics | Dynamics

Question:

A stone is dropped at rest from the top of a cliff. it is observed to hit the ground 5.78s later it falls an acceleration of -10m/s2. How high is the cliff?

Answer:

Height of the cliff equals:


h=gt22h = \frac {g t ^ {2}}{2}


where gg is acceleration due to gravity, tt is time.


h=105.7822=167mh = 10 \frac {5.78^{2}}{2} = 167 \, m


Answer: 167 m

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