Question #47943

An apple falls from a tree and hits the ground
9.41 m below.
With what speed will it hit the ground?
The acceleration of gravity is 9.8 m/s
2
.
Answer in units of m/s
1

Expert's answer

2014-10-17T00:51:52-0400

Answer on Question #47943, Physics, Mechanics | Kinematics | Dynamics

An apple falls from a tree and hits the ground 9.41 m below. With what speed will it hit the ground? The acceleration of gravity is 9.8 m/s². Answer in units of m/s

Solution:

The kinematic equation that describes an object's motion is:


vf2=vi2+2adv _ {f} ^ {2} = v _ {i} ^ {2} + 2 a d


The symbol dd stands for the displacement of the object. The symbol aa stands for the acceleration of the object. And the symbol vv stands for the velocity of the object; a subscript of ii after the vv indicates that the velocity value is the initial velocity value and a subscript of ff indicates that the velocity value is the final velocity value.


vi=0v _ {i} = 0d=9.41md = 9.41 \mathrm{m}a=g=9.8m/s2a = g = 9.8 \mathrm{m/s^2}vf=0+29.89.41=13.58m/sv _ {f} = \sqrt {0 + 2 * 9.8 * 9.41} = 13.58 \mathrm{m/s}


Answer: vf=13.58m/sv_{f} = 13.58 \, \mathrm{m/s}

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